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Explaining Buffer Overflows: Memory Corruption for Beginners

TL;DR: A structured introduction to stack memory, registers, and how input overflow leads to arbitrary code execution. Ideal for reverse engineering students.

Introduction to Stack-Based Overflows

A buffer overflow occurs when a program writes more data to a buffer than it was allocated to hold. This extra data overflows into adjacent memory spaces, corrupting them and potentially overwriting the instruction pointer (EIP/RIP) to control execution flow.

1. Memory Layout of a Program

When a process runs in memory, its virtual space is organized into several segments:

  • Text Segment: Contains the compiled machine instructions.
  • Data Segment: Contains initialized global variables.
  • BSS Segment: Contains uninitialized global variables.
  • Heap: Dynamically allocated memory (grows upward).
  • Stack: Local function variables, frame parameters, return addresses (grows downward).

2. Anatomy of an Overflow

Consider this vulnerable C code snippet:

#include <string.h>
void vuln_func(char *str) {
    char buffer[64];
    strcpy(buffer, str); // No bounds checking!
}
int main(int argc, char **argv) {
    vuln_func(argv[1]);
    return 0;
}

The stack layout inside vuln_func looks like this:

Memory Space Description
[ Buffer (64 bytes) ] Allocated space for local variable buffer
[ Saved EBP (4 bytes) ] Base Pointer of the calling function
[ Return Address / EIP (4 bytes) ] Address to return to after function finishes

If we supply 80 bytes of data, the strcpy function will copy all 80 bytes. The first 64 bytes fill the buffer, the next 4 overwrite the Saved EBP, and the next 4 overwrite the Return Address (EIP). By placing the address of a shellcode payload there, we can hijack the program execution.

Knowledge Verification Checkpoint

Answer this question to verify your understanding of this write-up.

Question: Which CPU register must an attacker overwrite to hijack execution flow in a stack buffer overflow?

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